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Topic: What's the most film you can put on a Potts Platter?
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John Pytlak
Film God
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Posts: 9987
From: Rochester, NY 14650-1922
Registered: Jan 2000
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posted 07-22-2002 11:18 AM
Why wouldn't you run it with an intermission, so you can use two platter levels?You can calculate roll diameter if you know the hub diameter, film thickness, and length of the print: ____________________________________________________________________ The roll diameter can be calculated from the following equation: D = Squareroot [ ( (48 x L x t) / Pi) + (C x C) ] Where: D is roll diameter in inches L is length of film roll in feet t is film thickness in inches (about 0.0053 for Kodak VISION Color Print film) C is core/hub diameter in inches For example, for a shipping reel with a 4-inch core, and a film thickness of 0.0053 inches, 2000 feet of film will have the following diameter: D = Squareroot [ ( (48 x 2000 x 0.0053) / Pi) + (4 x 4) ] = 13.3 inches ------------------ John P. Pytlak, Senior Technical Specialist Worldwide Technical Services, Entertainment Imaging Research Labs, Building 69, Room 7525A Rochester, New York, 14650-1922 USA Tel: +1 585 477 5325 Cell: +1 585 781 4036 Fax: +1 585 722 7243 e-mail: john.pytlak@kodak.com Web site: http://www.kodak.com/go/motion
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Steve Guttag
We forgot the crackers Gromit!!!
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Posts: 12814
From: Annapolis, MD
Registered: Dec 1999
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posted 07-22-2002 12:45 PM
This would be a rate of change problem...as such Calculus would be the tool. It would be a matter of expressing the diameter increasing in size as a function of film length. So you have Pi*Dmin=L. D is the variable since on the next revolution, D = Dmin + (2*Film thickness). Also this problem presumes that the film thickness is << D (which it is). This continues until D = Dmax. Now you are at a point where you can integrate D as it goes from min to max.Or...you can just use the formula John provided! Steve ------------------ "Old projectionists never die, they just changeover!"
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