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This topic comprises 2 pages: 1 2
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Author
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Topic: What size Xenon to use????
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John Pytlak
Film God
Posts: 9987
From: Rochester, NY 14650-1922
Registered: Jan 2000
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posted 07-28-2002 06:30 AM
A "rule of thumb" is 5 watts for each square foot of screen area for a matte white (gain=1) screen. Assumptions include a 2-blade (50% efficient) shutter, modern lens design, good alignment, etc.------------------ John P. Pytlak, Senior Technical Specialist Worldwide Technical Services, Entertainment Imaging Research Labs, Building 69, Room 7525A Rochester, New York, 14650-1922 USA Tel: +1 585 477 5325 Cell: +1 585 781 4036 Fax: +1 585 722 7243 e-mail: john.pytlak@kodak.com Web site: http://www.kodak.com/go/motion
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Steve Guttag
We forgot the crackers Gromit!!!
Posts: 12814
From: Annapolis, MD
Registered: Dec 1999
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posted 07-28-2002 02:07 PM
Depending on the projector and lenses used, I prefer 12h^2 or 13h^2. Where h = the height of the 1.85:1 image. Thus an older system with a 10 foot tall screen would need 1300 watts. If you have an efficient projector with one of the newer efficient lenses (like the ISCO Ultra Star PLUS lenses) that could be dropped to 1200 watts. As to gain screens, if they are pearlescent, they are normally in the range of 1.5-1.8. If it is a Stewart brand screen it will be as it is claimed (they offer several gains). Steve ------------------ "Old projectionists never die, they just changeover!"
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Steve Guttag
We forgot the crackers Gromit!!!
Posts: 12814
From: Annapolis, MD
Registered: Dec 1999
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posted 07-28-2002 10:05 PM
There would be enough unknowns in there to beg the question that if you are that savy, just use your calculator.Also, it would force Hurley and other common screen manufacturers to have a consistant gain. Steve ------------------ "Old projectionists never die, they just changeover!"
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John Pytlak
Film God
Posts: 9987
From: Rochester, NY 14650-1922
Registered: Jan 2000
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posted 07-29-2002 10:38 AM
Steve's formula and my "rule of thumb" give about the same answer:For a 10 x 23.9 foot screen (239 square feet) My rule of thumb: 5 x 239 = 1195 watts Steve's 12h^2 = 12 x 10^2 = 1200 watts Pat is correct that lamphouse efficiency is assumed to be typical of a modern lamphouse with good optical alignment. ------------------ John P. Pytlak, Senior Technical Specialist Worldwide Technical Services, Entertainment Imaging Research Labs, Building 69, Room 7525A Rochester, New York, 14650-1922 USA Tel: +1 585 477 5325 Cell: +1 585 781 4036 Fax: +1 585 722 7243 e-mail: john.pytlak@kodak.com Web site: http://www.kodak.com/go/motion
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John Pytlak
Film God
Posts: 9987
From: Rochester, NY 14650-1922
Registered: Jan 2000
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posted 07-29-2002 10:44 AM
The vertical lamphouse design of the ORC Optimax theoretically was more efficient in reducing infrared radiation, by using a 45-degree heat mirror that reflected visible light and passed the IR to a heatsink. As others have said, alignment was difficult, and the vertical lamp was prone to "candlelight flicker" due to a relatively unstable plasma.Likewise the vertical lamp design of the old Zeiss Ikon Xenosol III required two mirrors and "honeycomb" condensers, complicating alignment. This was the first xenon lamphouse I ever had to work with. ------------------ John P. Pytlak, Senior Technical Specialist Worldwide Technical Services, Entertainment Imaging Research Labs, Building 69, Room 7525A Rochester, New York, 14650-1922 USA Tel: +1 585 477 5325 Cell: +1 585 781 4036 Fax: +1 585 722 7243 e-mail: john.pytlak@kodak.com Web site: http://www.kodak.com/go/motion
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