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Topic: Modification for changing CP45 crossover frequencies
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Robert Minichino
Master Film Handler
Posts: 350
From: Haskell, NJ, USA
Registered: Dec 2005
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posted 10-12-2010 12:30 PM
The resistor value is R=7234316/f, where f is the frequency in Hz, and R is the resistance in ohms. Pick the closest value resistor.
The "LO" setting adds another resistor value to "HI" value, so if you want to pick a second, lower, frequency, find the resistor value for that frequency, subtract the "HI" value resistor, and that's the second resistor you want.
So if you want to set the center channel to have two selectable crossover points, one at 600 Hz and the other at 900 Hz, you'd start by calculating the high resistors:
Rhi = 7234316/900 = 8038 ohms (8.04k)
Now, calculate the low resistance:
Rlo = 7234316/600 = 12057 ohms (12.06k)
Subtract the two, to find the low resistors;
12.06k - 8.04k = 4.02k
So you would then install 12.06k resistors in R614, R616, R618, and R621, and 4.02k resistors in R613, R615, R617, and R619.
If you only one want frequency selection, just calculate the resistance, substitute the first four resistors per channel and leave the switch on "HI."
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